What will be the final values of i and j in the following C code? #include <stdio.h> int x = 0; int main() { int i = (f() + g()) || g(); int j = g() || (f() + g()); } int f() { if (x == 0) return x + 1; else return x - 1; } int g() { return x++; }

• A. i value is 1 and j value is 1
• B. i value is 0 and j value is 0
• C. i value is 1 and j value is undefined
• D. i and j value are undefined