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1. |
What should be the velocity of rotation of earth due to rotation about its own axis so that the weight of a person becomes \[\frac{2}{3}\] of the present weight at the equator? Equatorial radius of the earth is R |
A. | \[{{\left( \frac{2g}{3R} \right)}^{\frac{1}{2}}}\] |
B. | \[{{\left( \frac{g}{3R} \right)}^{\frac{1}{2}}}\] |
C. | \[{{\left( \frac{g}{7R} \right)}^{\frac{1}{2}}}\] |
D. | \[{{\left( \frac{g}{5R} \right)}^{\frac{1}{2}}}\] |
Answer» C. \[{{\left( \frac{g}{7R} \right)}^{\frac{1}{2}}}\] | |