What is the velocity v of a metallic ball of radius r falling in a tank of liquid at the instant when its acceleration is one -half that of a freely falling body? (The densities of metal and of liquid are $$\rho $$ and $$\sigma $$ respectively, and the viscosity of the liquid is $$\eta $$).

Question

TuteeHUB · Accepted Answer

$$\frac{2{{r}^{2}}g}{9\eta }(\rho -\sigma )$$

TuteeHUB · Answer

$$\frac{{{r}^{2}}g}{9\eta }(\rho -2\sigma )$$

TuteeHUB · Answer

$$\frac{{{r}^{2}}g}{9\eta }(2\rho -\sigma )$$

TuteeHUB · Answer

$$\frac{{{r}^{2}}g}{9\eta }(\rho -\sigma )$$

1.	What is the velocity v of a metallic ball of radius r falling in a tank of liquid at the instant when its acceleration is one -half that of a freely falling body? (The densities of metal and of liquid are \[\rho \] and \[\sigma \] respectively, and the viscosity of the liquid is \[\eta \]).
A.	\[\frac{{{r}^{2}}g}{9\eta }(\rho -2\sigma )\]
B.	\[\frac{{{r}^{2}}g}{9\eta }(2\rho -\sigma )\]
C.	\[\frac{{{r}^{2}}g}{9\eta }(\rho -\sigma )\]
D.	\[\frac{2{{r}^{2}}g}{9\eta }(\rho -\sigma )\]
Answer» D. \[\frac{2{{r}^{2}}g}{9\eta }(\rho -\sigma )\]

What is the velocity v of a metallic ball of radius r falling in a tank of liquid at the instant when its acceleration is one -half that of a freely falling body? (The densities of metal and of liquid are \[\rho \] and \[\sigma \] respectively, and the viscosity of the liquid is \[\eta \]).

Discussion

No Comment Found

Related MCQs

Reply to Comment