What is the output of this program?#include <iostream> #include <exception> using namespace std; class BaseClass { virtual void dummy() {} }; class DerivedClass: public BaseClass { int num; }; int main () { try { BaseClass * ptr1 = new DerivedClass; BaseClass * ptr2 = new BaseClass; DerivedClass * ptr3; ptr3 = dynamic_cast(ptr1); if (ptr3 == 0) cout << "Null pointer on first type-cast" << endl; ptr3 = dynamic_cast(ptr2); if (ptr3 == 0) cout << "Null pointer on second type-cast" << endl; } catch (exception& excep) { cout << "Exception: " << excep.what(); } return 0; }

Null pointer on first type-cast

Null pointer on second type-cast

What is the output of this program?#include <iostream> #include <excep

1.	What is the output of this program? #include <iostream> #include <exception> using namespace std; class BaseClass { virtual void dummy() {} }; class DerivedClass: public BaseClass { int num; }; int main () { try { BaseClass * ptr1 = new DerivedClass; BaseClass * ptr2 = new BaseClass; DerivedClass * ptr3; ptr3 = dynamic_cast(ptr1); if (ptr3 == 0) cout << "Null pointer on first type-cast" << endl; ptr3 = dynamic_cast(ptr2); if (ptr3 == 0) cout << "Null pointer on second type-cast" << endl; } catch (exception& excep) { cout << "Exception: " << excep.what(); } return 0; }
A.	Null pointer on first type-cast
B.	Null pointer on second type-cast
C.	Exception:
D.	All of above
E.	None of these
Answer» C. Exception:

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