1.

What is the maximum acceleration of the particle doing the SHM \[y=2\sin \left[ \frac{\pi t}{2}+\varphi  \right]\]where 2 is in cm [DCE 2003]

A.            \[\frac{\pi }{2}cm/{{s}^{2}}\]
B.            \[\frac{{{\pi }^{2}}}{2}cm/{{s}^{2}}\]
C.            \[\frac{\pi }{4}cm/{{s}^{2}}\]
D.            \[\frac{\pi }{4}cm/{{s}^{2}}\]
Answer» C.            \[\frac{\pi }{4}cm/{{s}^{2}}\]


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