What is the greatest number of 3 digits which when divided by 6, 9 and – McqOptions

MCQOPTIONS

1.	What is the greatest number of 3 digits which when divided by 6, 9 and 12 leaves a remainder of 3 in each case ?
A.	03
B.	39
C.	75
D.	96
Answer» D. 96

Discussion

No Comment Found

Related MCQs

Let N be the greatest number that will divide 1305, 4665 and 6905, leaving the same remainder in each case. Then sum of the digits in N is:
Reduce_x000D_ 128352_x000D_ to its lowest terms._x000D_ _x000D_ _x000D_ 238368
The H.C.F. of 9 , 12 , 18 and 21 is: 10 25 35 40
The least number which when divided by 4, 6, 8, 12 and 16 leaves remainder of 2 in each case is = ?
The HCF and LCM of two numbers are 8 and 48 respectively. If one of the number is 24, then the other number is=?
The H.C.F. of $$\frac{{9}}{{10}},$$ $$\frac{{12}}{{25}},$$ $$\frac{{18}}{{35}}$$ and $$\frac{{21}}{{40}}$$ is:
Which of the following fraction is the largest ?
Reduce $$\frac{{128352}}{{238368}}$$to its lowest terms.
The HCF and LCM of two numbers are 12 and 336 respectively. If one of the numbers is 84, the other is=?
A number which when divided by 10 leaves a remainder of 9, when divided by 9 leaves a remainder of 8, and when divided by 8 leaves a remainder of 7, is=?