What is the equilibrium constant for the reaction? \[{{P}_{4(s)}}+5{{O}_{2(g)}}\rightleftarrows {{P}_{4}}{{O}_{10(s)}}\]

\[{{K}_{C}}=\frac{\left[ {{P}_{4}}{{O}_{10}} \right]}{5\left[ {{P}_{4}} \right]\left[ {{O}_{2}} \right]}\]

\[{{K}_{C}}=\frac{1}{{{\left[ {{O}_{2}} \right]}^{5}}}\]

\[{{K}_{C}}={{\left[ {{O}_{2}} \right]}^{5}}\]

\[{{K}_{C}}=\frac{\left[ {{P}_{4}}{{O}_{10}} \right]}{5\left[ {{P}_{4}} \right]{{\left[ {{O}_{2}} \right]}^{5}}}\]

What is the equilibrium constant for the reaction? \[{{P}_{4(s)}}+5{{O

1.	What is the equilibrium constant for the reaction? \[{{P}_{4(s)}}+5{{O}_{2(g)}}\rightleftarrows {{P}_{4}}{{O}_{10(s)}}\]
A.	\[{{K}_{C}}=\frac{1}{{{\left[ {{O}_{2}} \right]}^{5}}}\]
B.	\[{{K}_{C}}=\frac{\left[ {{P}_{4}}{{O}_{10}} \right]}{5\left[ {{P}_{4}} \right]\left[ {{O}_{2}} \right]}\]
C.	\[{{K}_{C}}={{\left[ {{O}_{2}} \right]}^{5}}\]
D.	\[{{K}_{C}}=\frac{\left[ {{P}_{4}}{{O}_{10}} \right]}{5\left[ {{P}_{4}} \right]{{\left[ {{O}_{2}} \right]}^{5}}}\]
Answer» B. \[{{K}_{C}}=\frac{\left[ {{P}_{4}}{{O}_{10}} \right]}{5\left[ {{P}_{4}} \right]\left[ {{O}_{2}} \right]}\]

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What is the equilibrium constant for the reaction? \[{{P}_{4(s)}}+5{{O}_{2(g)}}\rightleftarrows {{P}_{4}}{{O}_{10(s)}}\]

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