What is the equation of the plane through z-axis and parallel to the line\[\frac{x-1}{\cos \theta }=\frac{y+2}{\sin \theta }=\frac{z-3}{0}\]?

What is the equation of the plane through z-axis and parallel to the l

1.	What is the equation of the plane through z-axis and parallel to the line\[\frac{x-1}{\cos \theta }=\frac{y+2}{\sin \theta }=\frac{z-3}{0}\]?
A.	\[x\,\,cot\,\theta +y=0\]
B.	\[x\,\,tan\,\,\theta -y=0\]
C.	\[x+y\,\,cot\,\theta =0\]
D.	\[x-y\,\,tan\,\theta =0\]
Answer» C. \[x+y\,\,cot\,\theta =0\]

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What is the equation of the plane through z-axis and parallel to the line\[\frac{x-1}{\cos \theta }=\frac{y+2}{\sin \theta }=\frac{z-3}{0}\]?

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