1.

What is the equation of load current for a differential amplifier with an active load?

A. I<sub>L</sub> = g<sub>m</sub>√óv<sub>d</sub>
B. I<sub>L</sub> = I<sub>q</sub> /2
C. I<sub>L</sub> = β×I<sub>q</sub>×( V<sub>in1</sub> – V<sub>in2</sub>)
D. I<sub>L</sub> = 2×g<sub>m</sub>/( V<sub>in1</sub> – V<sub>in2</sub>)
Answer» B. I<sub>L</sub> = I<sub>q</sub> /2


Discussion

No Comment Found

Related MCQs