What is the derivative of\[{{\tan }^{-1}}\left( \frac{\sqrt{1+{{x}^{2}}}-1}{x} \right)\] with respect to \[{{\tan }^{-1}}x\]?

What is the derivative of\[{{\tan }^{-1}}\left( \frac{\sqrt{1+{{x}^{2}

1.	What is the derivative of\[{{\tan }^{-1}}\left( \frac{\sqrt{1+{{x}^{2}}}-1}{x} \right)\] with respect to \[{{\tan }^{-1}}x\]?
A.	0
B.	\[\frac{1}{2}\]
C.	1
D.	x
Answer» C. 1

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What is the derivative of\[{{\tan }^{-1}}\left( \frac{\sqrt{1+{{x}^{2}}}-1}{x} \right)\] with respect to \[{{\tan }^{-1}}x\]?

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