What is the area of the portion of the curve\[y=sin\text{ }x\], lying between \[x=0,\text{ }y=0\] and\[x=2\pi \]?

What is the area of the portion of the curve\[y=sin\text{ }x\], lying

1.	What is the area of the portion of the curve\[y=sin\text{ }x\], lying between \[x=0,\text{ }y=0\] and\[x=2\pi \]?
A.	1 square unit
B.	2 square units
C.	4 square units
D.	8 square units
Answer» C. 4 square units

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What is the area of the portion of the curve\[y=sin\text{ }x\], lying between \[x=0,\text{ }y=0\] and\[x=2\pi \]?

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