What is \[\sin [co{{t}^{-1}}\{cos(ta{{n}^{-1}}x)]\] where \[x>0\], equal to?

\[\sqrt{\frac{({{x}^{2}}+2)}{({{x}^{2}}+1)}}\]

\[\sqrt{\frac{({{x}^{2}}+1)}{({{x}^{2}}+2)}}\]

\[\frac{({{x}^{2}}+1)}{({{x}^{2}}+2)}\]

\[\frac{({{x}^{2}}+2)}{({{x}^{2}}+1)}\]

What is \[\sin [co{{t}^{-1}}\{cos(ta{{n}^{-1}}x)]\] where \[x>0\], equ

1.	What is \[\sin [co{{t}^{-1}}\{cos(ta{{n}^{-1}}x)]\] where \[x>0\], equal to?
A.	\[\sqrt{\frac{({{x}^{2}}+1)}{({{x}^{2}}+2)}}\]
B.	\[\sqrt{\frac{({{x}^{2}}+2)}{({{x}^{2}}+1)}}\]
C.	\[\frac{({{x}^{2}}+1)}{({{x}^{2}}+2)}\]
D.	\[\frac{({{x}^{2}}+2)}{({{x}^{2}}+1)}\]
Answer» B. \[\sqrt{\frac{({{x}^{2}}+2)}{({{x}^{2}}+1)}}\]

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What is \[\sin [co{{t}^{-1}}\{cos(ta{{n}^{-1}}x)]\] where \[x>0\], equal to?

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