What is \[\int\limits_{0}^{1}{\frac{{{\tan }^{-1}}}{1+{{x}^{2}}}dx}\] equal to?

What is \[\int\limits_{0}^{1}{\frac{{{\tan }^{-1}}}{1+{{x}^{2}}}dx}\]

1.	What is \[\int\limits_{0}^{1}{\frac{{{\tan }^{-1}}}{1+{{x}^{2}}}dx}\] equal to?
A.	\[\frac{\pi }{4}\]
B.	\[\frac{\pi }{8}\]
C.	\[\frac{{{\pi }^{2}}}{8}\]
D.	\[\frac{{{\pi }^{2}}}{32}\]
Answer» E.

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What is \[\int\limits_{0}^{1}{\frac{{{\tan }^{-1}}}{1+{{x}^{2}}}dx}\] equal to?

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