What does derived class does not inherit from the base class?

1.	What does derived class does not inherit from the base class?
A.	friends
B.	operator = () members
C.	constructor and destructor
D.	All of above
E.	None of these
Answer» E. None of these

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What is the output of this program? <pre class="prettyprint lang-c">#include <iostream> using namespace std; class InterfaceClass { public: virtual void Display() = 0; }; class ClassA : public InterfaceClass { public: void Display() { int num = 10; cout << num; } }; class ClassB : public InterfaceClass { public: void Display() { cout < } }; int main() { ClassA object1; object1.Display(); ClassB object2; object2.Display(); return 0; } </pre>
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What is the output of this program? <pre class="prettyprint lang-c">#include <iostream> using namespace std; class Base { int K; public: void setInt(int num); int getInt(); }; class Derived : public Base { int L; public: void setL(int num); int multiply(); }; void Base::setInt(int num) { K = num; } int Base::getInt() { return K; } void Derived::setL(int num) { L = num; } int Derived::multiply() { return L * getInt(); } int main() { Derived object; object.setInt(12); object.setL(3); cout << object.multiply(); return 0; } </pre>
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What is the output of this program? <pre class="prettyprint lang-c">#include <iostream> using namespace std; class BaseClass { int A; public: void setA(int num1) { A = num1; } void showA() { cout << A < } }; class DerivedClass : private BaseClass { int B; public: void setAB(int num1, int num2) { setA(num1); B = num2; } void showAB() { showA(); cout < } }; int main() { DerivedClass object; object.setAB(15, 25); object.showAB(); return 0; } </pre>
What is the output of this program? <pre class="prettyprint lang-c">#include <iostream> using namespace std; class BaseClass { public: BaseClass(){} ~BaseClass(){} protected: private: }; class DerivedClass:public BaseClass { public: DerivedClass(){} DerivedClass(){} private: protected: }; int main() { cout << "The program exceuted" << endl; } </pre>
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What is the output of this program? <pre class="prettyprint lang-c">#include <iostream> using namespace std; class student { protected: int Rollno; public: void get_Rollno(int num) { Rollno = num; } void put_Rollno(void) { } }; class test:public student { protected: float Subject1,Subject2; public: void get_mark(float num1, float num2) { Subject1 = num1; Subject2 = num2; } void put_marks() { } }; class sports { protected: float score; public: void getscore(float s) { score = s; } void putscore(void) { } }; class result: public test, public sports { float total; public: void display(void); }; void result::display(void) { total = Subject1 + Subject2 + score; put_Rollno(); put_marks(); putscore(); cout << "Total Score = " << total << " n"; } int main() { result student; student.get_Rollno(101); student.get_mark(50.25, 42.52); student.getscore(7.0); student.display(); return 0; } </pre>
What is the output of this program? <pre class="prettyprint lang-c">#include <iostream> using namespace std; class BaseClass { public: virtual void print() const = 0; }; class DerivedClassA : virtual public BaseClass { public: void print() const { cout << " 5 "; } }; class DerivedClassB : virtual public BaseClass { public: void print() const { cout << "3"; } }; class Multiple : public DerivedClassA, DerivedClassB { public: void print() const { DerivedClassB::print(); } }; int main() { Multiple both; DerivedClassA objectA; DerivedClassB objectB; BaseClass *array[ 3 ]; array[ 0 ] = &both; array[ 1 ] = &objectA; array[ 2 ] = &objectB; for ( int K = 0; K < 3; K++ ) array[ K ] -> print(); return 0; } </pre>

What does derived class does not inherit from the base class?

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