We want to declare x, y and z as pointers of type int. The alias name given is: intpt The correct way to do this using the keyword typedef is:

int typedef* intptr; int x,y,z;

int typedef* intptr; intptr x,y,z;

typedef int* intptr; intptr x,y,z;

We want to declare x, y and z as pointers of type int. The alias name

1.	We want to declare x, y and z as pointers of type int. The alias name given is: intpt The correct way to do this using the keyword typedef is:
A.	int typedef* intptr; int x,y,z;
B.	typedef* intptr; int x,y,z;
C.	int typedef* intptr; intptr x,y,z;
D.	typedef int* intptr; intptr x,y,z;
Answer» E.

Discussion

No Comment Found

Related MCQs

typedef's have the advantage that they obey scope rules, that is they can be declared local to a function or a block whereas #define's always have a global effect.
Are the properties of i, j and x, y in the following program same? <pre> <code>typedef unsigned long int uli; uli i, j; unsigned long int x, y;</code></pre>
Is there any difference in the #define and typedef in the following code? <pre> <code>typedef char * string_t; #define string_d char *; string_t s1, s2; string_d s3, s4;</code></pre>
Is the following declaration acceptable? <pre> <code>typedef long no, *ptrtono; no n; ptrtono p;</code></pre>
In the following code snippet can we declare a new typedef named ptr even though struct employee has not been completely declared while using typedef? <pre> <code>typedef struct employee *ptr; struct employee { char name[20]; int age; ptr next; }</code></pre>
Point out the error in the following code? <pre> <code>typedef struct { int data; NODEPTR link; }*NODEPTR;</code></pre>
What will be the output of the program? <pre> <code>#include<stdio> typedef struct error {int warning, err, exception;} ERROR; int main() { ERROR e; e.err=1; printf("%d n", e.err); return 0; }</stdio></code></pre>
What will be the output of the program? <pre> <code>#include<stdio> int main() { typedef float f; static f *fptr; float fval = 90; fptr = &fval; printf("%f n", *fptr); return 0; }</stdio></code></pre>
What will be the output of the program? <pre> <code>#include<stdio> int main() { typedef int LONG; LONG a=4; LONG b=68; float c=0; c=b; b+=a; printf("%d,", b); printf("%f n", c); retu</stdio></code></pre>
What will be the output of the program? <pre> <code>#include<stdio> int main() { enum color{red, green, blue}; typedef enum color mycolor; mycolor m = red; printf("%d", m); return 0; }</stdio></code></pre>

We want to declare x, y and z as pointers of type int. The alias name given is: intpt The correct way to do this using the keyword typedef is:

Discussion

No Comment Found

Related MCQs

Reply to Comment