We have two sets of LR (1) items of LR (1) grammar described below. X->c.X, c/d X->c.X, $ X->.cX, c/d X->.cX, $ X->.d, c/d X->.d, $ Related to the merging of two sets in the corresponding parser, the statement that does not hold true is

Cannot be merged since look aheads are different.

Cannot be merged but will result in R-R conflict

Cannot be merged but will result in S-R conflict

We have two sets of LR (1) items of LR (1) grammar described below.

1.	We have two sets of LR (1) items of LR (1) grammar described below. X->c.X, c/d X->c.X, $ X->.cX, c/d X->.cX, $ X->.d, c/d X->.d, $ Related to the merging of two sets in the corresponding parser, the statement that does not hold true is
A.	Cannot be merged since look aheads are different.
B.	Cannot be merged but will result in R-R conflict
C.	Cannot be merged but will result in S-R conflict
D.	All of the above
Answer» E.

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We have two sets of LR (1) items of LR (1) grammar described below. X-&gt;c.X, c/d X-&gt;c.X, $ X-&gt;.cX, c/d X-&gt;.cX, $ X-&gt;.d, c/d X-&gt;.d, $ Related to the merging of two sets in the corresponding parser, the statement that does not hold true is

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We have two sets of LR (1) items of LR (1) grammar described below. X->c.X, c/d X->c.X, $ X->.cX, c/d X->.cX, $ X->.d, c/d X->.d, $ Related to the merging of two sets in the corresponding parser, the statement that does not hold true is