MCQOPTIONS
Saved Bookmarks
| 1. |
We have two (narrow) capillary tubes T1 and T2. Their lengths are l1 and l2 and radii of cross-section are r1 and r2 respectively. The rate of flow of water under a pressure difference P through tube T1 is 8cm3/sec. If l1 = 2l2 and r1 =r2, what will be the rate of flow when the two tubes are connected in series and pressure difference across the combination is same as before (= P) |
| A. | 4 cm3/sec |
| B. | (16/3) cm3/sec |
| C. | (8/17) cm3/sec |
| D. | None of these |
| Answer» C. (8/17) cm3/sec | |