We have a galvanometer of resistance \[25\,\Omega \]. It is shunted by a \[2.5\,\Omega \] wire. The part of total current that flows through the galvanometer is given as [AFMC 1998; MH CET 1999; Pb. PMT 2002]

• A.                    \[\frac{I}{{{I}_{0}}}=\frac{1}{11}\]
• B.                                      \[\frac{I}{{{I}_{0}}}=\frac{1}{10}\]
• C.                    \[\frac{I}{{{I}_{0}}}=\frac{3}{11}\]                           
• D.            \[\frac{I}{{{I}_{0}}}=\frac{4}{11}\]