\[\underset{\left( {{C}_{5}}{{H}_{10}}O \right)}{\mathop{\left( X \right)}}\,~\xrightarrow{{{H}_{3}}{{O}^{+}}}Y+Z\](Y and Z both give the lodoform test). The compound X is -

\[C{{H}_{3}}-CH=CH-O-C{{H}_{2}}-C{{H}_{3}}\]

\[C{{H}_{3}}-\underset{C{{H}_{3}}}{\overset{H}{\mathop{\underset{|}{\overset{|}{\mathop{C}}}\,}}}\,-O-C{{H}_{2}}-C{{H}_{3}}\]

\[C{{H}_{3}}-\underset{C{{H}_{2}}}{\overset{{}}{\mathop{\underset{||}{\overset{{}}{\mathop{C}}}\,}}}\,-O-C{{H}_{2}}-C{{H}_{3}}\]

\[\underset{\left( {{C}_{5}}{{H}_{10}}O \right)}{\mathop{\left( X \rig

1.	\[\underset{\left( {{C}_{5}}{{H}_{10}}O \right)}{\mathop{\left( X \right)}}\,~\xrightarrow{{{H}_{3}}{{O}^{+}}}Y+Z\](Y and Z both give the lodoform test). The compound X is -
A.	\[C{{H}_{3}}-CH=CH-O-C{{H}_{2}}-C{{H}_{3}}\]
B.	\[C{{H}_{3}}-\underset{C{{H}_{3}}}{\overset{H}{\mathop{\underset{\|}{\overset{\|}{\mathop{C}}}\,}}}\,-O-C{{H}_{2}}-C{{H}_{3}}\]
C.	\[C{{H}_{3}}-\underset{C{{H}_{2}}}{\overset{{}}{\mathop{\underset{\|\|}{\overset{{}}{\mathop{C}}}\,}}}\,-O-C{{H}_{2}}-C{{H}_{3}}\]
D.	Both [a] and [c]
Answer» D. Both [a] and [c]