\[\underset{x\to \infty }{\mathop{\lim }}\,\,{{\left( \frac{x+a}{x+b} \right)}^{x+b}}=\] [EAMCET 2001]

\[\underset{x\to \infty }{\mathop{\lim }}\,\,{{\left( \frac{x+a}{x+b}

1.	\[\underset{x\to \infty }{\mathop{\lim }}\,\,{{\left( \frac{x+a}{x+b} \right)}^{x+b}}=\] [EAMCET 2001]
A.	1
B.	\[{{e}^{b-a}}\]
C.	\[{{e}^{a-b}}\]
D.	\[{{e}^{b}}\]
Answer» D. \[{{e}^{b}}\]

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\[\underset{x\to \infty }{\mathop{\lim }}\,\,{{\left( \frac{x+a}{x+b} \right)}^{x+b}}=\] [EAMCET 2001]

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