\[\underset{x\to \infty }{\mathop{\lim }}\,{{\left( 1+\frac{2}{x} \right)}^{x}}=\]

\[\underset{x\to \infty }{\mathop{\lim }}\,{{\left( 1+\frac{2}{x} \rig

1.	\[\underset{x\to \infty }{\mathop{\lim }}\,{{\left( 1+\frac{2}{x} \right)}^{x}}=\]
A.	e
B.	\[\frac{1}{e}\]
C.	\[{{e}^{2}}\]
D.	None of these
Answer» D. None of these

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\[\underset{x\to \infty }{\mathop{\lim }}\,{{\left( 1+\frac{2}{x} \right)}^{x}}=\]

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