\[\underset{x\to \infty }{\mathop{\lim }}\,\frac{{{n}^{p}}{{\sin }^{2}}(n!)}{n+1},0

\[\underset{x\to \infty }{\mathop{\lim }}\,\frac{{{n}^{p}}{{\sin }^{2}

1.	\[\underset{x\to \infty }{\mathop{\lim }}\,\frac{{{n}^{p}}{{\sin }^{2}}(n!)}{n+1},0
A.	0
B.	\[\infty \]
C.	1
D.	None of these
Answer» B. \[\infty \]

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\[\underset{x\to \infty }{\mathop{\lim }}\,\frac{{{n}^{p}}{{\sin }^{2}}(n!)}{n+1},0

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