\[\underset{x\to \infty }{\mathop{\lim }}\,\frac{3{{x}^{2}}+2x-1}{2{{x}^{2}}-3x-3}=\]

\[\underset{x\to \infty }{\mathop{\lim }}\,\frac{3{{x}^{2}}+2x-1}{2{{x

1.	\[\underset{x\to \infty }{\mathop{\lim }}\,\frac{3{{x}^{2}}+2x-1}{2{{x}^{2}}-3x-3}=\]
A.	1
B.	3
C.	\[\frac{3}{2}\]
D.	\[-\frac{3}{2}\]
Answer» D. \[-\frac{3}{2}\]

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\[\underset{x\to \infty }{\mathop{\lim }}\,\frac{3{{x}^{2}}+2x-1}{2{{x}^{2}}-3x-3}=\]

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