\[\underset{x\to \infty }{\mathop{\lim }}\,\frac{2{{x}^{2}}-3x+1}{{{x}^{2}}-1}=\]

\[\underset{x\to \infty }{\mathop{\lim }}\,\frac{2{{x}^{2}}-3x+1}{{{x}

1.	\[\underset{x\to \infty }{\mathop{\lim }}\,\frac{2{{x}^{2}}-3x+1}{{{x}^{2}}-1}=\]
A.	1
B.	2
C.	?2
D.	None of these
Answer» C. ?2

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\[\underset{x\to \infty }{\mathop{\lim }}\,\frac{2{{x}^{2}}-3x+1}{{{x}^{2}}-1}=\]

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