\[\underset{x\to -2}{\mathop{\lim }}\,\frac{{{\sin }^{-1}}(x+2)}{{{x}^{2}}+2x}\] is equal to [Orissa JEE 2002]

\[\underset{x\to -2}{\mathop{\lim }}\,\frac{{{\sin }^{-1}}(x+2)}{{{x}^

1.	\[\underset{x\to -2}{\mathop{\lim }}\,\frac{{{\sin }^{-1}}(x+2)}{{{x}^{2}}+2x}\] is equal to [Orissa JEE 2002]
A.	0
B.	\[\infty \]
C.	?1/2
D.	None of these
Answer» D. None of these

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\[\underset{x\to -2}{\mathop{\lim }}\,\frac{{{\sin }^{-1}}(x+2)}{{{x}^{2}}+2x}\] is equal to [Orissa JEE 2002]

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