\[\underset{x\to 1}{\mathop{\lim }}\,\frac{x-1}{2{{x}^{2}}-7x+5}=\] [IIT 1976]

\[\underset{x\to 1}{\mathop{\lim }}\,\frac{x-1}{2{{x}^{2}}-7x+5}=\] [I

1.	\[\underset{x\to 1}{\mathop{\lim }}\,\frac{x-1}{2{{x}^{2}}-7x+5}=\] [IIT 1976]
A.	1/3
B.	1/11
C.	?1/3
D.	None of these
Answer» D. None of these

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\[\underset{x\to 1}{\mathop{\lim }}\,\frac{x-1}{2{{x}^{2}}-7x+5}=\] [IIT 1976]

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