\[\underset{x\to 0}{\mathop{\lim }}\,\left[ \frac{\sin (x+a)+\sin (a-x)-2\sin a}{x\sin x} \right]=\]

\[\underset{x\to 0}{\mathop{\lim }}\,\left[ \frac{\sin (x+a)+\sin (a-x

1.	\[\underset{x\to 0}{\mathop{\lim }}\,\left[ \frac{\sin (x+a)+\sin (a-x)-2\sin a}{x\sin x} \right]=\]
A.	\[\sin a\]
B.	\[\cos a\]
C.	\[-\sin a\]
D.	\[\frac{1}{2}\cos a\]
Answer» D. \[\frac{1}{2}\cos a\]

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\[\underset{x\to 0}{\mathop{\lim }}\,\left[ \frac{\sin (x+a)+\sin (a-x)-2\sin a}{x\sin x} \right]=\]

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