\[\underset{x\to 0}{\mathop{\lim }}\,\left( \frac{10\sin 9x}{9\sin 10x} \right)\left( \frac{8\sin 7x}{7\sin 8x} \right)\left( \frac{6\sin 5x}{5\sin 6x} \right)\left( \frac{4\sin 3x}{3\sin 4x} \right)\] \[\left( \frac{\sin x}{\sin 2x} \right)=\]

\[\underset{x\to 0}{\mathop{\lim }}\,\left( \frac{10\sin 9x}{9\sin 10x

1.	\[\underset{x\to 0}{\mathop{\lim }}\,\left( \frac{10\sin 9x}{9\sin 10x} \right)\left( \frac{8\sin 7x}{7\sin 8x} \right)\left( \frac{6\sin 5x}{5\sin 6x} \right)\left( \frac{4\sin 3x}{3\sin 4x} \right)\] \[\left( \frac{\sin x}{\sin 2x} \right)=\]
A.	\[\frac{63}{256}\]
B.	\[\frac{1}{6}\]
C.	\[\frac{6}{5}\]
D.	\[\frac{1}{2}\]
Answer» E.

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\[\underset{x\to 0}{\mathop{\lim }}\,\left( \frac{10\sin 9x}{9\sin 10x} \right)\left( \frac{8\sin 7x}{7\sin 8x} \right)\left( \frac{6\sin 5x}{5\sin 6x} \right)\left( \frac{4\sin 3x}{3\sin 4x} \right)\] \[\left( \frac{\sin x}{\sin 2x} \right)=\]

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