\[\underset{x\to 0}{\mathop{\lim }}\,\left[ \frac{1}{x}-\frac{\log (1+x)}{{{x}^{2}}} \right]\]=

\[\underset{x\to 0}{\mathop{\lim }}\,\left[ \frac{1}{x}-\frac{\log (1+

1.	\[\underset{x\to 0}{\mathop{\lim }}\,\left[ \frac{1}{x}-\frac{\log (1+x)}{{{x}^{2}}} \right]\]=
A.	½
B.	?1/2
C.	1
D.	?1
Answer» B. ?1/2

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\[\underset{x\to 0}{\mathop{\lim }}\,\left[ \frac{1}{x}-\frac{\log (1+x)}{{{x}^{2}}} \right]\]=

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