\[\underset{x\to 0}{\mathop{\lim }}\,{{\left\{ \frac{1+\operatorname{tanx}}{1+\sin x} \right\}}^{\cos ecx}}\] is equal to

\[\underset{x\to 0}{\mathop{\lim }}\,{{\left\{ \frac{1+\operatorname{t

1.	\[\underset{x\to 0}{\mathop{\lim }}\,{{\left\{ \frac{1+\operatorname{tanx}}{1+\sin x} \right\}}^{\cos ecx}}\] is equal to
A.	\[\frac{1}{e}\]
B.	1
C.	\[e\]
D.	\[{{e}^{2}}\]
Answer» C. \[e\]

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\[\underset{x\to 0}{\mathop{\lim }}\,{{\left\{ \frac{1+\operatorname{tanx}}{1+\sin x} \right\}}^{\cos ecx}}\] is equal to

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