\[\underset{x\to 0}{\mathop{\lim }}\,\frac{x\tan 2x-2x\tan x}{{{(1-\cos 2x)}^{2}}}\] is [IIT 1999]

\[\underset{x\to 0}{\mathop{\lim }}\,\frac{x\tan 2x-2x\tan x}{{{(1-\co

1.	\[\underset{x\to 0}{\mathop{\lim }}\,\frac{x\tan 2x-2x\tan x}{{{(1-\cos 2x)}^{2}}}\] is [IIT 1999]
A.	2
B.	?2
C.	\[\frac{1}{2}\]
D.	\[-\frac{1}{2}\]
Answer» D. \[-\frac{1}{2}\]

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\[\underset{x\to 0}{\mathop{\lim }}\,\frac{x\tan 2x-2x\tan x}{{{(1-\cos 2x)}^{2}}}\] is [IIT 1999]

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