\[\underset{x\to 0}{\mathop{\lim }}\,\frac{x\cos x-\sin x}{{{x}^{2}}\sin x}=\] [MNR 1984,86]

\[\underset{x\to 0}{\mathop{\lim }}\,\frac{x\cos x-\sin x}{{{x}^{2}}\s

1.	\[\underset{x\to 0}{\mathop{\lim }}\,\frac{x\cos x-\sin x}{{{x}^{2}}\sin x}=\] [MNR 1984,86]
A.	\[\frac{1}{3}\]
B.	\[-\frac{1}{3}\]
C.	1
D.	None of these
Answer» C. 1

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\[\underset{x\to 0}{\mathop{\lim }}\,\frac{x\cos x-\sin x}{{{x}^{2}}\sin x}=\] [MNR 1984,86]

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