\[\underset{x\to 0}{\mathop{\lim }}\,\frac{\sin x-x}{{{x}^{3}}}=\] [MNR 1980, 86]

\[\underset{x\to 0}{\mathop{\lim }}\,\frac{\sin x-x}{{{x}^{3}}}=\] [MN

1.	\[\underset{x\to 0}{\mathop{\lim }}\,\frac{\sin x-x}{{{x}^{3}}}=\] [MNR 1980, 86]
A.	\[\frac{1}{3}\]
B.	\[-\frac{1}{3}\]
C.	\[\frac{1}{6}\]
D.	\[-\frac{1}{6}\]
Answer» E.

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\[\underset{x\to 0}{\mathop{\lim }}\,\frac{\sin x-x}{{{x}^{3}}}=\] [MNR 1980, 86]

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