\[\underset{x\to 0}{\mathop{\lim }}\,\frac{\sin (\pi {{\cos }^{2}}x)}{{{x}^{2}}}=\] [IIT Screening 2001;UPSEAT 2001; MP PET 2002]

\[\underset{x\to 0}{\mathop{\lim }}\,\frac{\sin (\pi {{\cos }^{2}}x)}{

1.	\[\underset{x\to 0}{\mathop{\lim }}\,\frac{\sin (\pi {{\cos }^{2}}x)}{{{x}^{2}}}=\] [IIT Screening 2001;UPSEAT 2001; MP PET 2002]
A.	\[(-1,1)\]
B.	\[\pi \]
C.	\[\pi /2\]
D.	1
Answer» C. \[\pi /2\]

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\[\underset{x\to 0}{\mathop{\lim }}\,\frac{\sin (\pi {{\cos }^{2}}x)}{{{x}^{2}}}=\] [IIT Screening 2001;UPSEAT 2001; MP PET 2002]

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