\[\underset{x\to 0}{\mathop{\lim }}\,\frac{\sin 2x}{x}=\] [MNR 1990; UPSEAT 2000]

\[\underset{x\to 0}{\mathop{\lim }}\,\frac{\sin 2x}{x}=\] �

1.	\[\underset{x\to 0}{\mathop{\lim }}\,\frac{\sin 2x}{x}=\] [MNR 1990; UPSEAT 2000]
A.	0
B.	1
C.	½
D.	2
Answer» E.

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\[\underset{x\to 0}{\mathop{\lim }}\,\frac{\sin 2x}{x}=\] [MNR 1990; UPSEAT 2000]

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