\[\underset{x\to 0}{\mathop{\lim }}\,\frac{{{\sin }^{-1}}x-{{\tan }^{-1}}x}{{{x}^{3}}}\] is equal to [RPET 2000]

\[\underset{x\to 0}{\mathop{\lim }}\,\frac{{{\sin }^{-1}}x-{{\tan }^{-

1.	\[\underset{x\to 0}{\mathop{\lim }}\,\frac{{{\sin }^{-1}}x-{{\tan }^{-1}}x}{{{x}^{3}}}\] is equal to [RPET 2000]
A.	0
B.	1
C.	?1
D.	\[1/2\]
Answer» E.

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\[\underset{x\to 0}{\mathop{\lim }}\,\frac{{{\sin }^{-1}}x-{{\tan }^{-1}}x}{{{x}^{3}}}\] is equal to [RPET 2000]

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