\[\underset{x\to 0}{\mathop{\lim }}\,\frac{{{e}^{1/x}}-1}{{{e}^{1/x}}+1}=\]

\[\underset{x\to 0}{\mathop{\lim }}\,\frac{{{e}^{1/x}}-1}{{{e}^{1/x}}+

1.	\[\underset{x\to 0}{\mathop{\lim }}\,\frac{{{e}^{1/x}}-1}{{{e}^{1/x}}+1}=\]
A.	0
B.	1
C.	?1
D.	Does not exist
Answer» E.

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\[\underset{x\to 0}{\mathop{\lim }}\,\frac{{{e}^{1/x}}-1}{{{e}^{1/x}}+1}=\]

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