\[\underset{x\to 0}{\mathop{\lim }}\,\frac{{{a}^{x}}-{{b}^{x}}}{{{e}^{x}}-1}\]= [Kerala (Engg.) 2002]

\[\log \left( \frac{b}{a} \right)\]

\[\log \left( \frac{a}{b} \right)\]

\[\underset{x\to 0}{\mathop{\lim }}\,\frac{{{a}^{x}}-{{b}^{x}}}{{{e}^{

1.	\[\underset{x\to 0}{\mathop{\lim }}\,\frac{{{a}^{x}}-{{b}^{x}}}{{{e}^{x}}-1}\]= [Kerala (Engg.) 2002]
A.	\[\log \left( \frac{a}{b} \right)\]
B.	\[\log \left( \frac{b}{a} \right)\]
C.	\[\log (a\,b)\]
D.	\[\log \,(a+\,b)\]
Answer» B. \[\log \left( \frac{b}{a} \right)\]

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\[\underset{x\to 0}{\mathop{\lim }}\,\frac{{{a}^{x}}-{{b}^{x}}}{{{e}^{x}}-1}\]= [Kerala (Engg.) 2002]

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