\[\underset{x\to 0}{\mathop{\lim }}\,\frac{2{{\sin }^{2}}3x}{{{x}^{2}}}=\] [Roorkee 1982; DCE 1999]

\[\underset{x\to 0}{\mathop{\lim }}\,\frac{2{{\sin }^{2}}3x}{{{x}^{2}}

1.	\[\underset{x\to 0}{\mathop{\lim }}\,\frac{2{{\sin }^{2}}3x}{{{x}^{2}}}=\] [Roorkee 1982; DCE 1999]
A.	6
B.	9
C.	18
D.	3
Answer» D. 3

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\[\underset{x\to 0}{\mathop{\lim }}\,\frac{2{{\sin }^{2}}3x}{{{x}^{2}}}=\] [Roorkee 1982; DCE 1999]

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