\[\underset{x\to 0}{\mathop{\lim }}\,\frac{{{(1+x)}^{n}}-1}{x}=\] [Kurukshetra CEE 2002]

\[\underset{x\to 0}{\mathop{\lim }}\,\frac{{{(1+x)}^{n}}-1}{x}=\] [Kur

1.	\[\underset{x\to 0}{\mathop{\lim }}\,\frac{{{(1+x)}^{n}}-1}{x}=\] [Kurukshetra CEE 2002]
A.	n
B.	1
C.	?1
D.	None of these
Answer» B. 1

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\[\underset{x\to 0}{\mathop{\lim }}\,\frac{{{(1+x)}^{n}}-1}{x}=\] [Kurukshetra CEE 2002]

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