\[\underset{x\to 0}{\mathop{\lim }}\,\frac{1}{x}{{\cos }^{-1}}\left( \frac{1-{{x}^{2}}}{1+{{x}^{2}}} \right)\]is equal to

\[\underset{x\to 0}{\mathop{\lim }}\,\frac{1}{x}{{\cos }^{-1}}\left( \

1.	\[\underset{x\to 0}{\mathop{\lim }}\,\frac{1}{x}{{\cos }^{-1}}\left( \frac{1-{{x}^{2}}}{1+{{x}^{2}}} \right)\]is equal to
A.	1
B.	0
C.	2
D.	none of these
Answer» E.

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\[\underset{x\to 0}{\mathop{\lim }}\,\frac{1}{x}{{\cos }^{-1}}\left( \frac{1-{{x}^{2}}}{1+{{x}^{2}}} \right)\]is equal to

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