\[\underset{x\to 0}{\mathop{\lim }}\,\frac{{{(1+x)}^{5}}-1}{{{(1+x)}^{3}}-1}=\]

\[\underset{x\to 0}{\mathop{\lim }}\,\frac{{{(1+x)}^{5}}-1}{{{(1+x)}^{

1.	\[\underset{x\to 0}{\mathop{\lim }}\,\frac{{{(1+x)}^{5}}-1}{{{(1+x)}^{3}}-1}=\]
A.	0
B.	1
C.	5/3
D.	3/5
Answer» D. 3/5

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\[\underset{x\to 0}{\mathop{\lim }}\,\frac{{{(1+x)}^{5}}-1}{{{(1+x)}^{3}}-1}=\]

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