\[\underset{x\to 0}{\mathop{\lim }}\,\frac{{{(1+x)}^{1/2}}-{{(1-x)}^{1/2}}}{x}=\] [Roorkee 1979; RPET 1996]

\[\underset{x\to 0}{\mathop{\lim }}\,\frac{{{(1+x)}^{1/2}}-{{(1-x)}^{1

1.	\[\underset{x\to 0}{\mathop{\lim }}\,\frac{{{(1+x)}^{1/2}}-{{(1-x)}^{1/2}}}{x}=\] [Roorkee 1979; RPET 1996]
A.	0
B.	1/2
C.	1
D.	?1
Answer» D. ?1

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\[\underset{x\to 0}{\mathop{\lim }}\,\frac{{{(1+x)}^{1/2}}-{{(1-x)}^{1/2}}}{x}=\] [Roorkee 1979; RPET 1996]

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