1.

\[\underset{x\to 0}{\mathop{\lim }}\,\frac{1-\cos x}{{{\sin }^{2}}x}=\] [DSSE 1987]

A.                 \[\frac{1}{2}\]
B.                 \[-\frac{1}{2}\]
C.                 2
D.                 None of these
Answer» B.                 \[-\frac{1}{2}\]


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