\[\underset{x\to 0}{\mathop{\lim }}\,{{(1-ax)}^{\frac{1}{x}}}=\] [Karnataka CET 2003]

\[\underset{x\to 0}{\mathop{\lim }}\,{{(1-ax)}^{\frac{1}{x}}}=\] [Karn

1.	\[\underset{x\to 0}{\mathop{\lim }}\,{{(1-ax)}^{\frac{1}{x}}}=\] [Karnataka CET 2003]
A.	e
B.	\[{{e}^{-a}}\]
C.	1
D.	\[{{e}^{a}}\]
Answer» C. 1

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\[\underset{x\to 0}{\mathop{\lim }}\,{{(1-ax)}^{\frac{1}{x}}}=\] [Karnataka CET 2003]

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