\[\underset{n\to \infty }{\mathop{\lim }}\,{{({{3}^{n}}+{{4}^{n}})}^{\frac{1}{n}}}=\] [Karnataka CET 2003]

\[\underset{n\to \infty }{\mathop{\lim }}\,{{({{3}^{n}}+{{4}^{n}})}^{\

1.	\[\underset{n\to \infty }{\mathop{\lim }}\,{{({{3}^{n}}+{{4}^{n}})}^{\frac{1}{n}}}=\] [Karnataka CET 2003]
A.	3
B.	4
C.	\[\infty \]
D.	e
Answer» C. \[\infty \]

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\[\underset{n\to \infty }{\mathop{\lim }}\,{{({{3}^{n}}+{{4}^{n}})}^{\frac{1}{n}}}=\] [Karnataka CET 2003]

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