\[\underset{h\to 0}{\mathop{\lim }}\,\frac{\sqrt{x+h}-\sqrt{x}}{h}=\] [Roorkee 1983]

\[\underset{h\to 0}{\mathop{\lim }}\,\frac{\sqrt{x+h}-\sqrt{x}}{h}=\]

1.	\[\underset{h\to 0}{\mathop{\lim }}\,\frac{\sqrt{x+h}-\sqrt{x}}{h}=\] [Roorkee 1983]
A.	\[\frac{1}{2\sqrt{x}}\]
B.	\[\frac{1}{\sqrt{x}}\]
C.	\[2\sqrt{x}\]
D.	\[\sqrt{x}\]
Answer» B. \[\frac{1}{\sqrt{x}}\]

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\[\underset{h\to 0}{\mathop{\lim }}\,\frac{\sqrt{x+h}-\sqrt{x}}{h}=\] [Roorkee 1983]

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