\[\underset{\alpha \to \pi /4}{\mathop{\lim }}\,\frac{\sin \alpha -\cos \alpha }{\alpha -\frac{\pi }{4}}=\] [IIT 1977]

\[\underset{\alpha \to \pi /4}{\mathop{\lim }}\,\frac{\sin \alpha -\co

1.	\[\underset{\alpha \to \pi /4}{\mathop{\lim }}\,\frac{\sin \alpha -\cos \alpha }{\alpha -\frac{\pi }{4}}=\] [IIT 1977]
A.	\[\sqrt{2}\]
B.	\[1/\sqrt{2}\]
C.	1
D.	None of these
Answer» B. \[1/\sqrt{2}\]

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\[\underset{\alpha \to \pi /4}{\mathop{\lim }}\,\frac{\sin \alpha -\cos \alpha }{\alpha -\frac{\pi }{4}}=\] [IIT 1977]

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