\[\underset{\alpha \to \beta }{\mathop{\lim }}\,\left[ \frac{{{\sin }^{2}}\alpha -{{\sin }^{2}}\beta }{{{\alpha }^{2}}-{{\beta }^{2}}} \right]=\] [MP PET 2001]

\[\frac{\sin 2\beta }{2\beta }\]

\[\underset{\alpha \to \beta }{\mathop{\lim }}\,\left[ \frac{{{\sin }^

1.	\[\underset{\alpha \to \beta }{\mathop{\lim }}\,\left[ \frac{{{\sin }^{2}}\alpha -{{\sin }^{2}}\beta }{{{\alpha }^{2}}-{{\beta }^{2}}} \right]=\] [MP PET 2001]
A.	0
B.	1
C.	\[\frac{\sin \beta }{\beta }\]
D.	\[\frac{\sin 2\beta }{2\beta }\]
Answer» E.

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\[\underset{\alpha \to \beta }{\mathop{\lim }}\,\left[ \frac{{{\sin }^{2}}\alpha -{{\sin }^{2}}\beta }{{{\alpha }^{2}}-{{\beta }^{2}}} \right]=\] [MP PET 2001]

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