Ultraviolet light of wavelengths $${{\lambda }_{1}}$$ and $${{\lambda }_{2}}$$ when allowed to fall on hydrogen atoms in their ground state is found to liberate electrons with kinetic energy $$K.{{E}_{1}}$$ and $$K.{{E}_{2}}$$ respectively. Find the value of Planck's constant.

Question

TuteeHUB · Accepted Answer

None of These

TuteeHUB · Answer

$$h=\left| \frac{\left( K.{{E}_{2}}-K.{{E}_{1}} \right)\left( {{\lambda }_{1}}+{{\lambda }_{2}} \right)}{C\left( {{\lambda }_{1}}-{{\lambda }_{2}} \right)} \right|$$

TuteeHUB · Answer

$$h=\left| \frac{\left( K.{{E}_{1}}-K.{{E}_{2}} \right)\left( {{\lambda }_{2}}-{{\lambda }_{1}} \right)}{C{{\lambda }_{1}}{{\lambda }_{2}}} \right|$$

TuteeHUB · Answer

$$h=\left| \frac{\left( K.{{E}_{1}}-K.{{E}_{2}} \right){{\lambda }_{1}}{{\lambda }_{2}}}{C\left( {{\lambda }_{2}}-{{\lambda }_{1}} \right)} \right|$$

1.	Ultraviolet light of wavelengths \[{{\lambda }_{1}}\] and \[{{\lambda }_{2}}\] when allowed to fall on hydrogen atoms in their ground state is found to liberate electrons with kinetic energy \[K.{{E}_{1}}\] and \[K.{{E}_{2}}\] respectively. Find the value of Planck's constant.
A.	\[h=\left\| \frac{\left( K.{{E}_{2}}-K.{{E}_{1}} \right)\left( {{\lambda }_{1}}+{{\lambda }_{2}} \right)}{C\left( {{\lambda }_{1}}-{{\lambda }_{2}} \right)} \right\|\]
B.	\[h=\left\| \frac{\left( K.{{E}_{1}}-K.{{E}_{2}} \right)\left( {{\lambda }_{2}}-{{\lambda }_{1}} \right)}{C{{\lambda }_{1}}{{\lambda }_{2}}} \right\|\]
C.	\[h=\left\| \frac{\left( K.{{E}_{1}}-K.{{E}_{2}} \right){{\lambda }_{1}}{{\lambda }_{2}}}{C\left( {{\lambda }_{2}}-{{\lambda }_{1}} \right)} \right\|\]
D.	None of These
Answer» D. None of These

Ultraviolet light of wavelengths \[{{\lambda }_{1}}\] and \[{{\lambda }_{2}}\] when allowed to fall on hydrogen atoms in their ground state is found to liberate electrons with kinetic energy \[K.{{E}_{1}}\] and \[K.{{E}_{2}}\] respectively. Find the value of Planck's constant.

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